What is the maximum slew rate achievable with a 0.3ms rise time and a 45mT/m maximum gradient?

To determine the maximum slew rate achievable, one can use the formula that relates slew rate to the rise time and the maximum gradient strength. The slew rate (in Tesla per meter per second, T/m/s) can be calculated by dividing the maximum gradient (in T/m) by the rise time (in seconds).

In this question, the maximum gradient is 45 mT/m, or 0.045 T/m. The rise time is given as 0.3 ms, which converts to 0.0003 seconds.

Using the formula:

Slew Rate = Maximum Gradient / Rise Time

Now substituting in the values:

Slew Rate = 0.045 T/m / 0.0003 s = 150 T/m/s.

This computation confirms that the achievable maximum slew rate with the provided values is 150 T/m/s. Therefore, the correct choice is 150 T/m/s because it accurately reflects the relationship between the maximum gradient and the time required to reach that gradient.

Other options either overestimate or underestimate the slew rate based on incorrect calculations or assumptions regarding the time or gradient parameters.